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In the circuit arrangement shown two cells supply a current I to a load resistance R=9 . One cell has an emf E₁=9 ~V and internal resistance r₁=1 and the other cell has an emf E₂=6 ~V and internal resistance r₂=3 . The currents are as shown. Then,

Options

  1. AI₁=0.9 ~A and I₂=0.5 ~A .
  2. BI 0.85 ~A .
  3. Cif the cell of emf E₁ is removed, current I will be smaller.
  4. Dif the cell of emf E₂ is removed, current I will be smaller.

Correct answer

A. I₁=0.9 ~A and I₂=0.5 ~A .

Step-by-step solution

No Solution

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