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Olympiad workbook
Exam
Olympiad workbook
Subject
NSEP
Chapter
Electromagnetic Waves

Olympiad workbook · NSEP · Electromagnetic Waves

The magnetic field B =2 × 10^ -5 \ π(0.5 × 10^3 x+1.5 × 10^ 11 t)\...

The magnetic field B⃗=2×10−5sin⁡{π(0.5×103x+1.5×1011t)}j^T\quad \vec{B}=2 \times 10^{-5} \sin \left\{\pi\left(0.5 \times 10^3 x+1.5 \times 10^{11} t\right)\right\} \hat{j} T \quad represents a plane electromagnetic wave travelling in space with xx in meter and t in second. The correct statement(s) are

Options

  1. AThe wave length of the wave is 4.0 mm and its frequency is 75 GHz
  2. BThe energy density associated with the wave is nearly =316μJ/m3=316 \mu J / \mathrm{m}^3
  3. CThe electric field vector is E⃗=−6000sin⁡[π(0.5×103x−1.5×1011t)]k^Vm−1\vec{E}=-6000 \sin \left[\pi\left(0.5 \times 10^3 x-1.5 \times 10^{11} t\right)\right] \hat{k} \mathrm{Vm}^{-1}
  4. DThe electric field vector is E⃗=6000sin⁡[π(0.5×103x+1.5×1011t)]k^Vm−1\vec{E}=6000 \sin \left[\pi\left(0.5 \times 10^3 x+1.5 \times 10^{11} t\right)\right] \hat{k} \mathrm{Vm}^{-1}

Correct answer

D. The electric field vector is E⃗=6000sin⁡[π(0.5×103x+1.5×1011t)]k^Vm−1\vec{E}=6000 \sin \left[\pi\left(0.5 \times 10^3 x+1.5 \times 10^{11} t\right)\right] \hat{k} \mathrm{Vm}^{-1}

Step-by-step solution

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