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A constant force F applied to the lower block of mass 15 kg makes it slide between the upper block of mass 5 kg and the table below, as shown. The coefficients of static ( _s ) and kinetic ( _k ) friction between the lower block and the table are 0.5 and 0.4 respectively and those between the two blocks are 0.3 and 0.1 . The accelerations of the upper and the lower blocks are respectively

Options

  1. A1.96 ~m / s ^2 and 1.96 ~m / s ^2
  2. B1.96 ~m / s ^2 and 3.92 ~m / s ^2
  3. C0.98 ~m / s ^2 and 0.49 ~m / s ^2
  4. D0.98 ~m / s ^2 and 1.96 ~m / s ^2

Correct answer

D. 0.98 ~m / s ^2 and 1.96 ~m / s ^2

Step-by-step solution

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