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Olympiad workbook
Exam
Olympiad workbook
Subject
NSEP
Chapter
Laws of Motion

Olympiad workbook · NSEP · Laws of Motion

A constant force F applied to the lower block of mass 15 kg makes...

A constant force FF applied to the lower block of mass 15 kg makes it slide between the upper block of mass 5 kg and the table below, as shown. The coefficients of static (μs)andkinetic(\left(\mu_s\right) and kinetic (\mu_k)frictionbetweenthelowerblockandthetableare0.5and0.4respectivelyandthosebetweenthetwoblocksare0.3and0.1.Theaccelerationsoftheupperandthelowerblocksarerespectively<imgsrc="/api/proxy−image?url=https) friction between the lower block and the table are 0.5 and 0.4 respectively and those between the two blocks are 0.3 and 0.1 . The accelerations of the upper and the lower blocks are respectively <img src="/api/proxy-image?url=https%3A%2F%2Ffirebasestorage.googleapis.com%2Fv0%2Fb%2Fquantrexacademy-app.firebasestorage.app%2Fo%2Fquestions%252Ffigs%252FNEET%252FOlympiad%252F8SXgbFFhAGA0mDYOJrxJ7oKJSUBikp4MjNfPrZ6hJ1k.original.fullsize.png%3Falt%3Dmedia&clean=1&v=qxfig138" data-qx-orig-src="/assets/diagrams/qx-book-46f7247d5f683dcd.png" data-qx-storage-src="/assets/diagrams/qx-book-46f7247d5f683dcd.png"><br>

Options

  1. A1.96 m/s21.96 \mathrm{~m} / \mathrm{s}^2 and 1.96 m/s21.96 \mathrm{~m} / \mathrm{s}^2
  2. B1.96 m/s21.96 \mathrm{~m} / \mathrm{s}^2 and 3.92 m/s23.92 \mathrm{~m} / \mathrm{s}^2
  3. C0.98 m/s20.98 \mathrm{~m} / \mathrm{s}^2 and 0.49 m/s20.49 \mathrm{~m} / \mathrm{s}^2
  4. D0.98 m/s20.98 \mathrm{~m} / \mathrm{s}^2 and 1.96 m/s21.96 \mathrm{~m} / \mathrm{s}^2

Correct answer

D. 0.98 m/s20.98 \mathrm{~m} / \mathrm{s}^2 and 1.96 m/s21.96 \mathrm{~m} / \mathrm{s}^2

Step-by-step solution

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