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Olympiad workbook
Exam
Olympiad workbook
Subject
NSEP
Chapter
Laws of Motion

Olympiad workbook · NSEP · Laws of Motion

Two equal blocks, each of mass M , hang on either side of a...

Two equal blocks, each of mass M , hang on either side of a frictionless light pulley with a light string. A rider of mass mm is placed on one of the blocks (as shown). When the system is released, the block with rider descends a distance H till the rider is caught by a ring that allows the block to pass through. The system moves a further distance D taking time t . In such a situation, the acceleration due to gravity is Two equal blocks, each of mass M , hang on either side of a frictionless light pulley with a light string. A rider of

Options

  1. Ag=(2M+m)D22mHt2g=\frac{(2 M+m) D^2}{2 m H t^2}
  2. Bg=(M+m)D22mHt2g=\frac{(M+m) D^2}{2 m H t^2}
  3. Cg=(2M+m)DmHt2g=\frac{(2 M+m) D}{m H t^2}
  4. Dg=(M+2m)D2mHt2g=\frac{(M+2 m) D^2}{m H t^2}

Correct answer

A. g=(2M+m)D22mHt2g=\frac{(2 M+m) D^2}{2 m H t^2}

Step-by-step solution

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