Olympiad workbookNSEPNuclear Physics
The Nucleus ₁₀²³ Ne decays by - emission through the reaction ₁₀²³ Ne ₁₁²³ Na + _ -1 ^0 + v + energy The atomic masses are ₁₀²³ Ne =22.994466 u and ₁₁²³ N a=22.989770 u , _ -1 ^0 =0.000549 u . The maximum kinetic energy that the emitted electron can ever have is
Options
- A4.374 MeV
- B3.862 MeV
- C2.187 MeV
- D1.931 MeV
Correct answer
A. 4.374 MeV
Step-by-step solution
No solution