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Olympiad workbookNSEPNuclear Physics

The Nucleus ₁₀²³ Ne decays by - emission through the reaction ₁₀²³ Ne ₁₁²³ Na + _ -1 ^0 + v + energy The atomic masses are ₁₀²³ Ne =22.994466 u and ₁₁²³ N a=22.989770 u , _ -1 ^0 =0.000549 u . The maximum kinetic energy that the emitted electron can ever have is

Options

  1. A4.374 MeV
  2. B3.862 MeV
  3. C2.187 MeV
  4. D1.931 MeV

Correct answer

A. 4.374 MeV

Step-by-step solution

No solution

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