A ball of mass m_1 travels horizontally along the x -axis in the positive direction with an initial speed of v_0 . It collides with another ball of mass m_2 that is originally at rest. After the collision, the ball of

Correct answer: D. m_1 v_0=m_1 v_ 1 x +m_2 v_ 2 x No Solution

Olympiad workbook

Olympiad workbook · NSEP · Rotational Motion

A ball of mass m_1 travels horizontally along the x -axis in the...

A ball of mass

m_1

travels horizontally along the

x

-axis in the positive direction with an initial speed of

\mathrm{v}_0

. It collides with another ball of mass

\mathrm{m}_2

that is originally at rest. After the collision, the ball of mass

m_1

has velocity \left(v_{1 x} \hat{i}+v_{1 y} \hat{j}\right) and the ball of mass

m_2

has velocity \left(v_{2 x} \hat{i}+v_{2 y} \hat{j}\right)$. Identify the correct relationship(s)

A $0=\mathrm{m}_1 \mathrm{v}_{1 \mathrm{x}}+\mathrm{m}_2 \mathrm{v}_{2 \mathrm{x}}$
B $m_1 v_0=m_1 v_{1 y}+m_2 v_{2 y}$
C $0=\mathrm{m}_1 \mathrm{v}_{1 \mathrm{y}}+\mathrm{m}_2 \mathrm{v}_{2 \mathrm{y}}$
D $\mathrm{m}_1 \mathrm{v}_0=\mathrm{m}_1 \mathrm{v}_{1 \mathrm{x}}+\mathrm{m}_2 \mathrm{v}_{2 \mathrm{x}}$

D. $\mathrm{m}_1 \mathrm{v}_0=\mathrm{m}_1 \mathrm{v}_{1 \mathrm{x}}+\mathrm{m}_2 \mathrm{v}_{2 \mathrm{x}}$

No Solution