Olympiad workbookNSEPRotational Motion
A small block A of mass 2 kg is attached to a spring of force constant 1200 Nm ⁻¹ , and rests on a smooth horizontal surface at x=0 as shown in figure. A second block B of mass 1 kg slides along the surface towards A at 6 ~ms ⁻¹ and sticks to it. Assuming that the collision occurs at t=0 , position x (in meter) of block A as a function of time t is expressed as
Options
- Ax=0.173 20 t
- Bx=0.1 40 t
- Cx=-0.173 10 t
- Dx =-0.1 20 t
Correct answer
D. x =-0.1 20 t
Step-by-step solution
No Solution