Let N be the number of ways of distributing 8 chocolates of different brands among 3 children such that each child gets at least one chocolate, and no two children get the same number of chocolates. Find the sum of the digits of N .

Question

Quantrex Academy · Accepted Answer

Correct answer: 24

aligned & 8 (1,2,5) or (1,3,4) & Number of ways |8 |2 |5 |1 |3 + |8 |1 |3 |4 |3 & = ( 8 7 6 2 + 8 7 6 5 6 ) 6 & =56 6(3+5) 56 48=2688 & Sum of digits =24 aligned

Let N be the number of ways of distributing 8 chocolates of different brands among 3 children such that each child gets at least one chocolate, and no two children get the same number of chocolates. Find the sum of the digits of N .

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