Let A= m: m . an integer and the roots of x^2+m x + 2020 = 0 are positive integers) and B= (n: n . an integer and the roots of x^2+2020 x+ n=0 are negative integers). Suppose a is the largest element of A and b is the smallest element of B

Question

Let A= m: m . an integer and the roots of x^2+m x + 2020 = 0 are positive integers) and B= (n: n . an integer and the roots of x^2+2020 x+ n=0 are negative integers). Suppose a is the largest element of A and b is the smallest element of B . Find the sum of digits of a+b .

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Correct answer: 26

=2020 where , N and m=-( + ) is least when , are 20 and 101. So a=-121 Now + =-2020 where and are negative integers. So n= . is least if , are -1 and -2019. So b=2019 a+b=1898 Sum of digits =26

Let A= m: m . an integer and the roots of x^2+m x + 2020 = 0 are positive integers) and B= (n: n . an integer and the roots of x^2+2020 x+ n=0 are negative integers). Suppose a is the largest element of A and b is the smallest element of B . Find the sum of digits of a+b .

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