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Olympiad workbook
Exam
Olympiad workbook
Subject
IOQM
Chapter
Vector Algebra

Olympiad workbook · IOQM · Vector Algebra

Let D, E, F be points on the sides B C, C A, A B of a triangle A B...

Let D,E,FD, E, F be points on the sides BC,CA,ABB C, C A, A B of a triangle ABCA B C, respectively. Suppose AD,BE,CFA D, B E, C F are concurrent at PP. If PF/PC=2/3,PE/PB=2/7P F / P C=2 / 3, P E / P B=2 / 7 and PD/PA=m/nP D / P A=m / n, where m,nm, n are positive integers with gcd⁡(m,n)=1\operatorname{gcd}(m, n)=1, find m+nm+n.Let D, E, F be points on the sides B C, C A, A B of a triangle A B C , respectively. Suppose A D, B E, C F are

Correct answer

45

Step-by-step solution

∵PFPC=23⇒PFCF=25=Δ1+Δ3Δ...(i)\begin{aligned} & \because \frac{P F}{P C}=\frac{2}{3} \\ & \Rightarrow \quad \frac{P F}{C F}=\frac{2}{5}=\frac{\Delta_1+\Delta_3}{\Delta}...(i) \end{aligned} Let D, E, F be points on the sides B C, C A, A B of a triangle A B C , respectively. Suppose A D, B E, C F are
Similarly 29=Δ2+Δ6Δ\quad \frac{2}{9}=\frac{\Delta_2+\Delta_6}{\Delta}...(ii)andmm+n=Δ4+Δ5Δand \quad \frac{m}{m+n}=\frac{\Delta_4+\Delta_5}{\Delta}...(iii) Adding (i), (ii) and (iii); we get 25+29+mm+n=1⇒mm+n=1−2845⇒mm+n=1745⇒28m=17n⇒mn=1728⇒m+n=45\begin{aligned} & \frac{2}{5}+\frac{2}{9}+\frac{m}{m+n}=1 \\ & \Rightarrow \frac{m}{m+n}=1-\frac{28}{45} \\ & \Rightarrow \frac{m}{m+n}=\frac{17}{45} \\ & \Rightarrow 28 m=17 n \\ & \Rightarrow \frac{m}{n}=\frac{17}{28} \\ & \Rightarrow m+n=45 \end{aligned}
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