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JEE Main 202429 JanuaryEvening Shift
Exam
JEE Main
Year
2024
Date
29 January
Shift
Evening Shift
Subject
Mathematics
Chapter
Application of Derivatives

JEE Main 2024 · 29 January · Evening Shift · Mathematics · Application of Derivatives

The function f(x) = 2x + 3x(2)/(3), x ∈ R , has

The function f(x)=2x+3x23,x∈Rf\left(x\right) = 2x + 3x\dfrac{2}{3}, x \in R, hasThe function f(x) = 2x + 3x(2)/(3), x ∈ R , has

Options

  1. Aexactly one point of local minima and no point of local maxima
  2. Bexactly one point of local maxima and no point of local minima
  3. Cexactly one point of local maxima and exactly one point of local minima
  4. Dexactly two points of local maxima and exactly one point of local minima

Correct answer

C. exactly one point of local maxima and exactly one point of local minima

Step-by-step solution

Given: f(x)=2x+3(x)23f ( x ) = 2x + 3 ( x) \dfrac{2}{3}

⇒f′(x)=2+2x−13⇒ {f}^{'}\left(x\right) = 2 + 2x\dfrac{- 1}{3}

⇒f′(x)=2(1+1x13)⇒ {f}^{'}\left(x\right) = 2\left(1 + \dfrac{1}{x\dfrac{1}{3}}\right)

⇒f′(x)=2(x13+1x13)⇒ {f}^{'}\left(x\right) = 2\left(\dfrac{x\dfrac{1}{3} + 1}{x\dfrac{1}{3}}\right)

The function f(x) = 2x + 3x(2)/(3), x ∈ R , has

The function changes from positive to negative at x=1x = 1 and from negative to positive at x=0x = 0

So, the point of local maxima \left(M\right)isatis atx = - 1and thepointoflocalminima(m)and the point of local minima \left(m\right) at x=0x = 0

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