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JEE Main 202127 JulyEvening Shift
Exam
JEE Main
Year
2021
Date
27 July
Shift
Evening Shift
Subject
Mathematics
Chapter
Application of Derivatives

JEE Main 2021 · 27 July · Evening Shift · Mathematics · Application of Derivatives

Let f: (a, b) → R be twice differentiable function such that f(x) =...

Let f:(a,b)→Rf: \left(a, b\right) \to R be twice differentiable function such that f(x)=∫axg(t)dtf\left(x\right) = {∫}_{a}^{x}g\left(t\right)dt for a differentiable function g(x).</u>Ifg\left(x\right) .</u> Iff\left(x\right)=0hasexactlyfivedistinctrootsin(a,b),= 0has exactly five distinct roots in \left(a, b\right), then g(x)g\left(x\right){g}^{'}\left(x\right)=0= 0 has at least :Let f: (a, b) → R be twice differentiable function such that f(x) = ∫ _ a ^ x g(t)dt for a differentiable function g(x)

Options

  1. Atwelve roots in (a,b)\left(a, b\right)
  2. Bfive roots in (a,b)\left(a, b\right)
  3. Cseven roots in (a,b)\left(a, b\right)
  4. Dthree roots in (a,b)\left(a, b\right)

Correct answer

C. seven roots in (a,b)\left(a, b\right)

Step-by-step solution

Let f:(a,b)→Rf: \left(a, b\right) \to R be twice differentiable function such that f(x)=∫axg(t)dtf\left(x\right) = {∫}_{a}^{x}g\left(t\right)dt for a differentiable function g(x),g\left(x\right),

Let f: (a, b) → R be twice differentiable function such that f(x) = ∫ _ a ^ x g(t)dt for a differentiable function g(x)

Now, f(x)=∫axg(t)dtf\left(x\right) = {∫}_{a}^{x}g\left(t\right)dt

Since, f(x)f\left(x\right) has 55 roots

and f′(x){f}^{'}\left(x\right) has atleast 44 roots

g(x)g\left(x\right) has atleast 44 roots

Therefore, g′(x){g}^{'}\left(x\right) has atleast 33 roots.

Hence, g(x)g′(x)g\left(x\right){g}^{'}\left(x\right) has atleast 77 roots.

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