JEE Main2013MathematicsApplication of DerivativesActual

If the curves x^2 + y^2 4 =1 and y^3=16 x intersect at right angles, then a value of is :

Options

A2
B4 3
C1 2
D3 4

Correct answer

B. 4 3

Step-by-step solution

aligned & x^2 + y^2 4 =1 2 x + 2 y 4 d y d x =0 & d y d x = -4 x y & y^3=16 x 3 y^2 d y d x =16 d y d x = 16 3 y^2 aligned Since curves intersects at right angles -4 x y 16 3 y^2 =-1 3 y^3=64 x

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