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JEE Main2011MathematicsApplication of DerivativesActual

The shortest distance between line y-x=1 and curve x=y^2 is

Options

  1. A3 2 8
  2. B8 3 2
  3. C4 3
  4. D3 4

Correct answer

A. 3 2 8

Step-by-step solution

P= (y^2, y ) Perpendicular distance from P to x-y+1=0 is |y^2-y+1 | 2 aligned & y ^2- y +1>0 y R & Coefficient y ^2>0 & Min value = 1 2 ( 4 ac - b ^2 4 a )= 3 4 2 aligned

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