JEE Main2008MathematicsApplication of DerivativesActual
How many real solutions does the equation x^7+14 x^5+16 x^3+30 x-560=0 have?
Options
- A7
- B1
- C3
- D5
Correct answer
B. 1
Step-by-step solution
aligned & x^7+14 x^5+16 x^3+30 x-560=0 & Let f(x)=x^7+14 x^5+16 x^3+30 x & f^ (x)=7 x^6+70 x^4+48 x^2+30>0 x aligned f(x) is an increasing function x .