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JEE Main2002MathematicsApplication of DerivativesActual

The maximum distance from origin of a point on the curve x=a t-b ( a t b )y=a t-b ( a t b ) , both a, b>0 is

Options

  1. Aa - b
  2. Ba + b
  3. Ca^2+b^2
  4. Da^2-b^2

Correct answer

A. a - b

Step-by-step solution

Distance of origin from (x, y)= x^2+y^2 = a^2+b^2-2 a b (t- a t b ) = a^2+b^2-2 a b [ (t- a t b )=1 ]=a-b

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