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JEE Main 202522 JanuaryMorning Shift
Exam
JEE Main
Year
2025
Date
22 January
Shift
Morning Shift
Subject
Mathematics
Chapter
Basics of Mathematics

JEE Main 2025 · 22 January · Morning Shift · Mathematics · Basics of Mathematics

The product of all solutions of the equation e^ 5( _ e x)^2+3 =x^8,...

The product of all solutions of the equation e5(log⁡ex)2+3=x8,x>0\mathrm{e}^{5\left(\log _{\mathrm{e}} x\right)^2+3}=x^8, x\gt0, is :

Options

  1. Ae8/5e^{8 / 5}
  2. Be6/5e^{6 / 5}
  3. Ce2\mathrm{e}^2
  4. De

Correct answer

A. e8/5e^{8 / 5}

Step-by-step solution

e5(ln⁡x)2+3=x8⇒ℓne5(ln⁡x)2+3=ℓnn8⇒5(ln⁡x)2+3=8ℓnx(ℓnx=t)⇒5t2−8t+3=0t1+t2=85ln⁡x1x2=85x1X2=e8/5\begin{aligned} & \mathrm{e}^{5(\ln x)^2+3}=\mathrm{x}^8 \\ & \Rightarrow \ell \mathrm{ne}^{5(\ln x)^2+3}=\ell \mathrm{nn}^8 \\ & \Rightarrow 5(\ln \mathrm{x})^2+3=8 \ell \mathrm{nx} \\ & (\ell \mathrm{nx}=\mathrm{t}) \\ & \Rightarrow 5 \mathrm{t}^2-8 \mathrm{t}+3=0 \\ & \quad \mathrm{t}_1+\mathrm{t}_2=\frac{8}{5} \\ & \quad \ln \mathrm{x}_1 \mathrm{x}_2=\frac{8}{5} \\ & \mathrm{x}_1 \mathrm{X}_2=\mathrm{e}^{8 / 5}\end{aligned}
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