If A = \ x ∈ R: |x| < 2\ and B = \ x ∈ R: |x - 2| ≥ 3\ ; then

A = \left\{x \in R: \left|x\right| < 2\right\}

and

B = \left\{x \in R: \left|x - 2\right| \ge 3\right\};

then

Options

B. $B - A = R - \left(- 2, 5\right)$

$A = \left\{x: x \in \left(- 2,2\right)\right\}$

$B = \left\{x: x \in ( - \infty, - 1 ] \cup [ 5, \left\infty\right)\right\}$

$A \cap B = \left\{x: x \in ( - 2, - 1 ]\right\}$

$A \cup B = \left\{x: x \in \left(- \infty, 2\right) \cup \left[5, \infty )\right\right\}$

$A - B = \left\{x: x \in \left(- 1,2\right)\right\}$

$B - A = \left\{x: x \in \left(- \infty, \left- 2\right] \cup \right\left[5, \left\infty\right)\right\right\}$