JEE Main2018MathematicsBasics of MathematicsActual
Let S = x ∈ R : x ≥ 0 & 2 x - 3 + x x - 6 + 6 = 0 . Then S :
Options
- AContains exactly four elements
- BIs an empty set
- CContains exactly one element
- DContains exactly two elements
Correct answer
D. Contains exactly two elements
Step-by-step solution
2 x - 3 + x x - 6 + 6 = 0 Let x = t > 0 2 t - 3 + t t - 6 + 6 = 0 ⇒ 2 t - 3 = - t 2 - 6 t + 6 ⇒ 2 t - 3 = - t 2 - 6 t + 9 + 3 So the equation 2 solutions.