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JEE Main 202120 JulyEvening Shift
Exam
JEE Main
Year
2021
Date
20 July
Shift
Evening Shift
Subject
Mathematics
Chapter
Binomial Theorem

JEE Main 2021 · 20 July · Evening Shift · Mathematics · Binomial Theorem

For the natural numbers m, n, if ( 1 - y ) ^ m ( 1 + y ) ^ n = 1 +...

For the natural numbers m,n,m, n, if (1−y)m(1+y)n=1+a1y+a2y2+….+am+nym+n( 1 - y{)}^{m} ( 1 + y{)}^{n} = 1 + {a}_{1}y + {a}_{2}{y}^{2} + \ldots . + {a}_{m + n}{y}^{m + n} and a1=a2=10,{a}_{1} = {a}_{2} = 10, then the value of m+n,m + n, is equal to:

Options

  1. A8888
  2. B6464
  3. C100100
  4. D8080

Correct answer

D. 8080

Step-by-step solution

We have,

(1−y)m(1+y)n( 1 - y{)}^{m} ( 1 + y{)}^{n}

=(C0m−C1my+C2my2+...+Cmm(−1)mym)(C0n+C1ny+C2ny2+...+Cnnyn)= \left(C0 m - C1 m y + C2 m {y}^{2} + . . . + Cm m {\left(- 1\right)}^{m}{y}^{m}\right)\left(C0 n + C1 n y + C2 n {y}^{2} + . . . + Cn n {y}^{n}\right)

Coefficient of y(a1)=1⋅C1n+C1m(−1)y\left({a}_{1}\right) = 1 \cdot C1 n + C1 m ( - 1 )

=n−m=10…(1)= n - m = 10 \ldots \left(1\right)

Coefficient of y2(a2){y}^{2}\left({a}_{2}\right)

=1C2n−C1mC1n+1mC2=10= 1 C2 n - C1 m C1 n + {1}^{m}{C}_{2} = 10

⇒n(n−1)2−m⋅n+m(m−1)2=10⇒ \dfrac{n ( n - 1 )}{2} - m \cdot n + \dfrac{m ( m - 1 )}{2} = 10

⇒m2+n2−2mn−(n+m)=20⇒ {m}^{2} + {n}^{2} - 2mn - ( n + m ) = 20

⇒(n−m)2−(n+m)=20⇒ ( n - m{)}^{2} - ( n + m ) = 20

⇒n+m=80…⇒ n + m = 80 \ldots\left(2\right)</p><p>Byequation(1)</p><p>By equation \left(1\right) and \left(2\right)</p><p></p><p>m = 35, n = 45</p><p>Hence,</p><p>Hence,m + n = 80

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