JEE Main 202227 JuneEvening Shift
- Exam
- JEE Main
- Year
- 2022
- Date
- 27 June
- Shift
- Evening Shift
- Subject
- Mathematics
- Chapter
- Differential Equations
JEE Main 2022 · 27 June · Evening Shift · Mathematics · Differential Equations
Let y = y(x) be the solution of the differential equation (1 - x ^...
Let be the solution of the differential equation \left(1 - {x}^{2}\right)dy = \left(xy + \left({x}^{3} + 2\right)\sqrt{1 - {x}^{2}}\right)dx, - 1 < x < 1y\left(0\right) = 0{∫}_{- \dfrac{1}{2}}^{\dfrac{1}{2}}\sqrt{1 - {x}^{2}}y\left(x\right)dx = k{k}^{- 1} is equal to
Correct answer
0
Step-by-step solution
Given,
So,required value