JEE Main2004MathematicsDifferential EquationsActual
The solution of the differential equation y d x+ (x+x^2 y ) d y=0 is
Options
- A- 1 x y =C
- B- 1 x y + y=C
- C1 x y + y=C
- Dy=C x
Correct answer
B. - 1 x y + y=C
Step-by-step solution
y d x+x d y+x^2 y d y=0 d(x y) x^2 y^2 + 1 y d y=0 - 1 x y + y=C