A person has three different bags and four different books. The number of ways, in which he can put these books in the bags so that no bag is empty, is:

Step-by-step solution

To ensure no bag is empty, exactly one bag must contain 2 books and the other two bags must contain 1 book each. The number of ways to choose 2 books out of 4 to be kept together is ⁴C₂ = 6 Now, we have 3 units (one pair of books and two single books) to be distributed into the 3 different bags. The number of ways to distribute these 3 units into 3 bags is 3! = 6 Total number of ways = 6 6 = 36 Answer: 36