Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main20266 April 2026Morning ShiftMathematicsPermutation and CombinationActual

The number of 4 -letter words, with or without meaning, each consisting of two vowels and two consonants that can be formed from the letters of the word INCONSEQUENTIAL, without repeating any letter, is:

Options

  1. A2670
  2. B2840
  3. C2920
  4. D3600

Correct answer

D. 3600

Step-by-step solution

The given word is INCONSEQUENTIAL. The vowels present in the word are I, O, E, U, A. There are 5 distinct vowels. The consonants present in the word are N, C, S, Q, T, L. There are 6 distinct consonants. We need to form 4 -letter words consisting of 2 vowels and 2 consonants without repeating any letter. This means all 4 letters in the formed word must be distinct. Number of ways to select 2 distinct vowels from 5 distinct vowels = ⁵C₂ = 5 4 2 = 10 Number of ways to select 2 distinct consonants from 6 distinct cons

Practice Permutation and Combination on Quantrex Academy →

More from Permutation and Combination

All Permutation and Combination questions Full Permutation and Combination list All JEE Main PYQs