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JEE Main 20266 AprilMorning Shift
Exam
JEE Main
Year
2026
Date
6 April
Shift
Morning Shift
Subject
Mathematics
Chapter
Permutation and Combination

JEE Main 2026 · 6 April · Morning Shift · Mathematics · Permutation and Combination

The number of 4 -letter words, with or without meaning, each...

The number of 44-letter words, with or without meaning, each consisting of two vowels and two consonants that can be formed from the letters of the word INCONSEQUENTIAL, without repeating any letter, is:

Options

  1. A26702670
  2. B28402840
  3. C29202920
  4. D36003600

Correct answer

D. 36003600

Step-by-step solution

The given word is INCONSEQUENTIAL.

The vowels present in the word are I, O, E, U, A. There are 55 distinct vowels.

The consonants present in the word are N, C, S, Q, T, L. There are 66 distinct consonants.

We need to form 44-letter words consisting of 22 vowels and 22 consonants without repeating any letter. This means all 44 letters in the formed word must be distinct.

Number of ways to select 22 distinct vowels from 55 distinct vowels = 5C2=5×42=10^{5}C_{2} = \dfrac{5 \times 4}{2} = 10

Number of ways to select 22 distinct consonants from 66 distinct consonants = 6C2=6×52=15^{6}C_{2} = \dfrac{6 \times 5}{2} = 15

Number of ways to arrange the 44 selected letters = 4!=244! = 24

Total number of 44-letter words that can be formed = 10×15×24=360010 \times 15 \times 24 = 3600

Answer: 36003600
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