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JEE Main 202528 JanuaryMorning Shift
Exam
JEE Main
Year
2025
Date
28 January
Shift
Morning Shift
Subject
Mathematics
Chapter
Permutation and Combination

JEE Main 2025 · 28 January · Morning Shift · Mathematics · Permutation and Combination

The number of different 5 digit numbers greater than 50000 that can...

The number of different 5 digit numbers greater than 50000 that can be formed using the digits 0 , 1,2,3,4,5,6,71,2,3,4,5,6,7, such that the sum of their first and last digits should not be more than 8 , is

Options

  1. A4608
  2. B5720
  3. C5719
  4. D4607

Correct answer

D. 4607

Step-by-step solution

$\begin{array}{lll} \text{ Case I } & 5 \ldots \ldots & 0 \\ \text{ Case II } & 5 \ldots \ldots & \\ & 5 & 1 \\ & 5 & 3 \\ & 6 & 0 \\ & 6 & 1 \\ & 6 & 2 \\ & 7 & 0 \\ & 7 & 1 \end{array}9 \times(8 \times 8 \times 8)=4608but50000isnotincluded,sototalnumbersbut 50000 is not included, so total numbers4608-1=4607
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