JEE Main202522 Jan 2025Evening ShiftMathematicsPermutation and CombinationActual
In a group of 3 girls and 4 boys, there are two boys B₁ and B₂ . The number of ways, in which these girls and boys can stand in a queue such that all the girls stand together, all the boys stand together, but B₁ and B₂ are not adjacent to each other, is :
Options
- A96
- B144
- C120
- D72
Correct answer
B. 144
Step-by-step solution
Total - when B ₁ and B ₂ are together =2!(3!4!)-2!(3!(3!2!))=144