The number of five-digit numbers, greater than 40000 and divisible by 5 , which can be formed using the digits 0 , 1 , 3 , 5 , 7 and 9 without repetition, is equal to

Step-by-step solution

We need to find the number of 5 digit numbers greater than 40000 and divisible by 5 . Case I : Numbers start with 5 . Here if the number starts with 5 it should end with 0 to be divisible by 5 . Case II : Number starts with 7 and the last digit can have 0 or 5 . Case III : The number starts with 9 and the last digit should have 0 or 5 . Total numbers = 120 . Hence this is the correct option.