The total number of three-digit numbers, with one digit repeated...

For three digit number we have following cases,

Case I: When digit zero is repeated

Number of numbers $= C1 9 = 9$

Case II: When digit zero is present but not repeated

Number of numbers $= C1 9 \cdot 2 ! = 18$

Case III: When digit zero is not present

Number of numbers $= 9 \cdot 8 \cdot \dfrac{3 !}{2 !} = 216$

Total number of numbers $= 243$