Let n be a non-negative integer. Then the number of divisors of the form 4 n + 1 of the number 10 10 · 11 11 · 13 13 is equal to _____.

Step-by-step solution

Let N = 2 10 × 5 10 × 11 11 × 13 13 Now, power of 2 must be zero, Power of 5 can be anything, Power of 13 can be anything. But, power of 11 should be even. So, required number of divisors is 1 × 11 × 14 × 6 = 924 .