The sum of all the 4 -digit distinct numbers that can be formed with the digits 1 , 2 , 2 and 3 is:

Step-by-step solution

Digits are 1 ,   2 ,   2 ,   3 total distinct numbers 4 ! 2 ! = 12 . total numbers when 1 at unit place is 3 . 2 at unit place is 6 3 at unit place is 3 . So, sum = ( 3 + 12 + 9 ) 10 3 + 10 2 + 10 + 1 = ( 1111 ) × 24 = 26664