Team A ' ' consists of 7 boys and n girls and Team B ' ' has 4 boys and 6 girls. If a total of 52 single matches can be arranged between these two teams when a boy plays against a boy and a girl plays against a girl, then n

Question

Team A ' ' consists of 7 boys and n girls and Team B ' ' has 4 boys and 6 girls. If a total of 52 single matches can be arranged between these two teams when a boy plays against a boy and a girl plays against a girl, then n is equal to:

Quantrex Academy · Accepted Answer

Correct answer: C. 4

Total matches between boys of both team = C 1 7 &#215; C 1 4 = 28 Total matches between girls of both team = C 1 n &#215; C 1 6 = 6 n Given, 28 + 6 n = 52 &#8658; n = 4

Team A ' ' consists of 7 boys and n girls and Team B ' ' has 4 boys and 6 girls. If a total of 52 single matches can be arranged between these two teams when a boy plays against a boy and a girl plays against a girl, then n is equal to:

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Correct answer

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Team A &#39; &#39; consists of 7 boys and n girls and Team B &#39; &#39; has 4 boys and 6 girls. If a total of 52 single matches can be arranged between these two teams when a boy plays against a boy and a girl plays against a girl, then n is equal to:

Options

Correct answer

Step-by-step solution

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Team A ' ' consists of 7 boys and n girls and Team B ' ' has 4 boys and 6 girls. If a total of 52 single matches can be arranged between these two teams when a boy plays against a boy and a girl plays against a girl, then n is equal to: