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JEE Main 202125 FebruaryMorning Shift
Exam
JEE Main
Year
2021
Date
25 February
Shift
Morning Shift
Subject
Mathematics
Chapter
Permutation and Combination

JEE Main 2021 · 25 February · Morning Shift · Mathematics · Permutation and Combination

The total number of positive integral solutions (x, y, z) such that...

The total number of positive integral solutions (x,y,z)\left(x, y, z\right) such that xyz=24xyz = 24 is :

Options

  1. A4545
  2. B3030
  3. C3636
  4. D2424

Correct answer

B. 3030

Step-by-step solution

We have,

xyz=24xyz = 24

⇒xyz=23×31⇒ xyz = {2}^{3} \times {3}^{1}

Let

x=2α1×3β1x = {2}^{{\alpha}_{1}} \times {3}^{{\beta}_{1}}

y=2α2×3β2y = {2}^{{\alpha}_{2}} \times {3}^{{\beta}_{2}}

z=2α3×3β2z = {2}^{{\alpha}_{3}} \times {3}^{{\beta}_{2}}

where,

α1+α2+α3=3...(i)</p><p>{\alpha}_{1} + {\alpha}_{2} + {\alpha}_{3} = 3 . . . \left(i\right)</p><p>{\beta}_{1} + {\beta}_{2} + {\beta}_{3} = 1 . . . . \left(ii\right)</p><p>Numberofnon−negativeintegralsolutionfor(i)</p><p>Number of non-negative integral solution for \left(i\right)

=C25=10= C2 5 = 10

Number of non-negative integral solution for \left(ii\right)</p><p></p><p>= C2 3 = 3</p><p>Totalnumberofpositiveintegralsolutions(x,y,z)</p><p>Total number of positive integral solutions \left(x, y, z\right) such that xyz=24xyz = 24 is

=10×3=30= 10 \times 3 = 30

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