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JEE Main 201912 AprilEvening Shift
Exam
JEE Main
Year
2019
Date
12 April
Shift
Evening Shift
Subject
Mathematics
Chapter
Permutation and Combination

JEE Main 2019 · 12 April · Evening Shift · Mathematics · Permutation and Combination

A group of students comprises of 5 boys and n girls. If the number...

A group of students comprises of 55 boys and n girls. If the number of ways, in which a team of 33 students can randomly be selected from this group such that there is at least one boy and at least one girl in each team, is 1750,1750, then n is equal to

Options

  1. A2424
  2. B2727
  3. C2525
  4. D2828

Correct answer

C. 2525

Step-by-step solution

(5) (n)
Boys Girls
22 11
11 22
Here total number of ways

=5C2×nC1+5C1×nC2=1750= { }^{5} {C}_{2} \times { }^{n} {C}_{1} {+}^{5} {C}_{1} \times { }^{n} {C}_{2} = 1750

⇒10n+5n(n−1)2=1750⇒ 10\text{n} + 5\dfrac{\text{n}( \text{n} - 1 )}{2} = 1750

⇒n2+3n−700=0⇒ n^{2} + 3\text{n} - 700 = 0

⇒n=−28,25⇒ \text{n} = - 28, 25

n\text{n} cannot be negative

Hence n=25\text{n} = 25
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