The number of ways in which 5 boys and 3 girls can be seated on a round table if a particular boy B 1 and a particular girl G 1 never sit adjacent to each other, is:

Step-by-step solution

Number of ways = Total - when B 1   &   G 1 sit together Total ways in which 5   boys + 3   girls = 8 people can be arranged is 7 ! Now, when B 1   &   G 1 sit together the number of ways (other 6 and B 1 G 1 grouped together) is 6 ! × 2 ! Hence, the required numer of ways is 7 ! - 6 ! 2 ! = 5 × 6 !