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JEE Main 20172 April
Exam
JEE Main
Year
2017
Date
2 April
Subject
Mathematics
Chapter
Permutation and Combination

JEE Main 2017 · 2 April · Mathematics · Permutation and Combination

A man X has 7 friends, 4 of them are ladies and 3 are men. His wife...

A man XX has 77 friends, 44 of them are ladies and 33 are men. His wife YY also has 77 friends, 33 of them are ladies and 44 are men. Assume XX and YY have no common friends. Then the total number of ways in which XX and YY together can throw a party inviting 33 ladies and 33 men, so that 33 friends of each of XX and YY are in this party is:A man X has 7 friends, 4 of them are ladies and 3 are men. His wife Y also has 7 friends, 3 of them are ladies and 4

Options

  1. A485485
  2. B468468
  3. C469469
  4. D484484

Correct answer

A. 485485

Step-by-step solution

Here, m - men and L - ladies

A man X has 7 friends, 4 of them are ladies and 3 are men. His wife Y also has 7 friends, 3 of them are ladies and 4

Total=(9×16)+(1)+(9×36)+(16)= \left(9 \times 16\right) + \left(1\right) + \left(9 \times 36\right) + \left(16\right)

=144+1+324+16= 144 + 1 + 324 + 16

=485= 485
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