JEE Main2017MathematicsPermutation and CombinationActual
A man X has 7 friends, 4 of them are ladies and 3 are men. His wife Y also has 7 friends, 3 of them are ladies and 4 are men. Assume X and Y have no common friends. Then the total number of ways in which X and Y together can throw a party inviting 3 ladies and 3 men, so that 3 friends of each of X and Y are in this party is:
Options
- A485
- B468
- C469
- D484
Correct answer
A. 485
Step-by-step solution
Here, m - men and L - ladies Total = 9 × 16 + 1 + 9 × 36 + 16 = 144 + 1 + 324 + 16 = 485