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JEE Main2015MathematicsPermutation and CombinationActual

The number of integers greater than 6000 that can be formed, using the digits 3 , 5 , 6 , 7 and 8 , without repetition is

Options

  1. A72
  2. B216
  3. C192
  4. D120

Correct answer

C. 192

Step-by-step solution

4 digit and 5 digit numbers are possible. 4 digit numbers: 6 / 7 / 8 ↑ ¯ ↑ ¯ ↑ ¯ ↑ ¯ 3 4 3 2           Total numbers possible = 3 . 4 . 3 . 2 = 72 5 digit numbers ↑ ¯ ↑ ¯ ↑ ¯ ↑ ¯ ↑ ¯ 5 4 3 2 1           Total numbers possible = 5 . 4 . 3 . 2 . 1 = 120 ∴ Total numbers = 72 + 120 = 192

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