JEE Main2015MathematicsPermutation and CombinationActual
The number of integers greater than 6000 that can be formed, using the digits 3 , 5 , 6 , 7 and 8 , without repetition is
Options
- A72
- B216
- C192
- D120
Correct answer
C. 192
Step-by-step solution
4 digit and 5 digit numbers are possible. 4 digit numbers: 6 / 7 / 8 ↑ ¯ ↑ ¯ ↑ ¯ ↑ ¯ 3 4 3 2           Total numbers possible = 3 . 4 . 3 . 2 = 72 5 digit numbers ↑ ¯ ↑ ¯ ↑ ¯ ↑ ¯ ↑ ¯ 5 4 3 2 1           Total numbers possible = 5 . 4 . 3 . 2 . 1 = 120 ∴ Total numbers = 72 + 120 = 192