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JEE Main 20154 April
Exam
JEE Main
Year
2015
Date
4 April
Subject
Mathematics
Chapter
Permutation and Combination

JEE Main 2015 · 4 April · Mathematics · Permutation and Combination

The number of integers greater than 6000 that can be formed, using...

The number of integers greater than 60006000 that can be formed, using the digits 3,5,6,73, 5, 6, 7 and 88, without repetition is

Options

  1. A7272
  2. B216216
  3. C192192
  4. D120120

Correct answer

C. 192192

Step-by-step solution

44 digit and 55 digit numbers are possible.

44 digit numbers:

{6/7/8↑¯↑¯↑¯↑¯3432Totalnumberspossible=3 . 4 . 3 . 2=72\begin{cases}6 / 7 / 8 & & & \\ \overset{¯}{↑} & \overset{¯}{↑} & \overset{¯}{↑} & \overset{¯}{↑} \\ 3 & 4 & 3 & 2\end{cases} Total numbers possible = \text{3 . 4 . 3 . 2} = \text{72}

55 digit numbers

{↑¯↑¯↑¯↑¯↑¯54321Totalnumberspossible=5 . 4 . 3 . 2 . 1=120\begin{cases}\overset{¯}{↑} & \overset{¯}{↑} & \overset{¯}{↑} & \overset{¯}{↑} & \overset{¯}{↑} \\ 5 & 4 & 3 & 2 & 1\end{cases} Total numbers possible = \text{5 . 4 . 3 . 2 . 1} = \text{120}

∴Total numbers=72+120=192∴ \text{Total numbers} = 72 + 120 = 192

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