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JEE Main2002MathematicsPermutation and CombinationActual

Five digit number divisible by 3 is formed using 0, 1, 2, 3, 4, 6 and 7 without repetition. Total number of such numbers are

Options

  1. A312
  2. B3125
  3. C120
  4. D216

Correct answer

D. 216

Step-by-step solution

Required numbers are 5 !+5 !-4 !=216

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