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From a lot containing 10 defective and 90 non-defective bulbs, 8 bulbs are selected one by one with replacement. Then the probability of getting at least 7 defective bulbs is

Options

  1. A67 10⁸
  2. B7 10⁷
  3. C81 10⁸
  4. D73 10⁸

Correct answer

D. 73 10⁸

Step-by-step solution

Binomial distribution with n=8 , p= 1 10 , q= 9 10 . P(X 7) = P(X=7) + P(X=8) P(X=7) = 8 7 ( 1 10 )^7 ( 9 10 ) = 72 10^8 P(X=8) = ( 1 10 )^8 = 1 10^8 P(X 7) = 73 10^8

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