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JEE Main 202624 JanuaryMorning Shift
Exam
JEE Main
Year
2026
Date
24 January
Shift
Morning Shift
Subject
Mathematics
Chapter
Probability

JEE Main 2026 · 24 January · Morning Shift · Mathematics · Probability

From a lot containing 10 defective and 90 non-defective bulbs, 8...

From a lot containing 10 defective and 90 non-defective bulbs, 8 bulbs are selected one by one with replacement. Then the probability of getting at least 7 defective bulbs is

Options

  1. A67108\frac{67}{10^{8}}
  2. B7107\frac{7}{10^{7}}
  3. C81108\frac{81}{10^{8}}
  4. D73108\frac{73}{10^{8}}

Correct answer

D. 73108\frac{73}{10^{8}}

Step-by-step solution

Binomial distribution with n=8n=8, p=110p=\frac{1}{10}, q=910q=\frac{9}{10}.
P(X≥7)=P(X=7)+P(X=8)P(X \ge 7) = P(X=7) + P(X=8)
P(X=7)=(87)(110)7(910)=72108P(X=7) = \binom{8}{7}\left(\frac{1}{10}\right)^7\left(\frac{9}{10}\right) = \frac{72}{10^8}
P(X=8)=(110)8=1108P(X=8) = \left(\frac{1}{10}\right)^8 = \frac{1}{10^8}
P(X≥7)=73108P(X \ge 7) = \frac{73}{10^8}
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