A person throws two fair dice. He wins Rs. 15 for throwing a doublet (same numbers on the two dice), wins Rs 12 when the throw results in the sum of 9 , and loses Rs. 6 for any other outcome on the throw. Then the expected gain/loss (in Rs.

Question

A person throws two fair dice. He wins Rs. 15 for throwing a doublet (same numbers on the two dice), wins Rs 12 when the throw results in the sum of 9 , and loses Rs. 6 for any other outcome on the throw. Then the expected gain/loss (in Rs.) of the person is:

Quantrex Academy · Accepted Answer

Correct answer: A. 1 2 loss

win Rs. 15 &#8594; number of cases = 6 win Rs. &#160; 12 &#8594; number of cases &#160; = 4 loss Rs. 6 &#8594; number of cases = 26 p (expected gain/loss) &#160; = 15 &#215; 6 36 + 12 &#215; 4 36 - 6 &#215; 26 36 = - 1 2

A person throws two fair dice. He wins Rs. 15 for throwing a doublet (same numbers on the two dice), wins Rs 12 when the throw results in the sum of 9 , and loses Rs. 6 for any other outcome on the throw. Then the expected gain/loss (in Rs.) of the person is:

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