If the probability of hitting a target by a shooter, in any shot is 1 3 , then the minimum number of independent shots at the target required by him so that the probability of hitting the target at least once is greater than 5 6 , is:

Step-by-step solution

P hitting   target = 1 3 Let number of trials = n P h i t t i n g    t a r g e t    a t l e a s t   o n c e = 1 - P not   hit = 1 - 2 3 n > 5 6 ⇒ 1 6 > 2 3 n So minimum number of trials = 5