JEE Main2014MathematicsProbabilityActual
A number x is chosen at random from the set 1 , 2,3,4, ., 100 . Define the event: A = the chosen number x satisfies (x-10)(x-50) (x-30) 0 Then P ( A ) is:
Options
- A0.71
- B0.70
- C0.51
- D0.20
Correct answer
A. 0.71
Step-by-step solution
Given (x-10)(x-50) (x-30) 0 Let x 10, x 50 equation will be true x 50 as ( x-50 x-30 ) 0, x [10,30) (x-10)(x-50) x-30 0 x [10,30) Total value of x between 10 to 30 is 20 . Total values of x between 50 to 100 including 50 and 100 is 51 . Total values of x=51+20=71 P( ~A )= 71 100 =0.71