JEE Main2009MathematicsProbabilityActual
One ticket is selected at random from 50 tickets numbered 00,01,02, , 49 . Then the probability that the sum of the digits on the selected ticket is 8 , given that the product of these digits is zero, equals
Options
- A1 14
- B1 7
- C5 14
- D1 50
Correct answer
A. 1 14
Step-by-step solution
S= 00,01,02, .49 Let A be the even that sum of the digits on the selected ticket is 8 then A= 08,17,26,35,44 Let B be the event that the product of the digits is zero B= 00,01,02,03, .09,10,20,30,40 A B= 8 Required probability =P(A / B)= P(A B) P(B) = 1 50 14 50 = 1 14