JEE Main2004MathematicsProbabilityActual
A random variable X has the probability distribution: array |c|c|c|c|c|c|c|c|c| X : & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 p ( X ): & 0.15 & 0.23 & 0.12 & 0.10 & 0.20 & 0.08 & 0.07 & 0.05 array For the events E= X is a prime number and F= X < 4 , the probability P(E F) is
Options
- A0.87
- B0.77
- C0.35
- D0.50
Correct answer
B. 0.77
Step-by-step solution
P(E F)=P(E)+P(F)-P(E F)=0.62+0.50-0.35=0.77