JEE Main202628 January 2026Morning ShiftMathematicsQuadratic EquationActual

If , , where < , are the roots of the equation x²-( +3) x+3=0 such that 1 - 1 = 1 3 , then the sum of all possible values of is

Options

Correct answer

B. 6

Step-by-step solution

+ = +3 , = 3 . 1 - 1 = - = 1 3 , so - = 3 = 1 . ( - )^2 = ( + )^2 - 4 : 1 ^2 = ( +3)^2 ^2 - 12 1 = ( +3)^2 - 12 = ^2 - 6 + 9 ^2 - 6 + 8 = 0 = 2 or = 4 . Both values satisfy < (verified). Sum = 2 + 4 = 6 .

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