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The values of ' a ' for which one root of the equation x^2-(a+1) x+a^2+a-8=0 exceeds 2 and the other is lesser than 2 , are given by :

Options

  1. A3 < a < 10
  2. Ba 10
  3. C-2 < a < 3
  4. Da -2

Correct answer

C. -2 < a < 3

Step-by-step solution

x^2-(a+1) x+a^2+a-8=0 Since roots are different, therefore D >0 aligned & (a+1)^2-4 (a^2+a-8 )>0 & (a-3)(3 a+1) 0 and 3 a+1 3 and a 0 a - 11 3 - 11 3 < a < 3 -2 < a < 3

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