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JEE Main20266 April 2026Morning ShiftMathematicsSequences and SeriesActual

The value of 1^3 - 2^3 + 3^3 - + 15^3 is:

Options

  1. A1706
  2. B1856
  3. C1982
  4. D2403

Correct answer

B. 1856

Step-by-step solution

The given series is S = 1^3 - 2^3 + 3^3 - 4^3 + + 15^3 . This can be rewritten as the sum of all cubes up to 15 minus twice the sum of cubes of even numbers up to 14 : S = (1^3 + 2^3 + 3^3 + + 15^3) - 2(2^3 + 4^3 + 6^3 + + 14^3) S = _ k=1 ¹⁵ k^3 - 2 2^3 (1^3 + 2^3 + 3^3 + + 7^3) S = _ k=1 ¹⁵ k^3 - 16 _ k=1 ⁷ k^3 Using the formula for the sum of cubes _ k=1 ^ n k^3 = ( n(n+1) 2 )^2 : _ k=1 ¹⁵ k^3 = ( 15 16 2 )^2 = (120)^2 = 14400 _ k=1 ⁷ k^3 = ( 7 8 2 )^2 = (28)^2 = 784 Substituting these values back into the expres

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