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JEE Main 202623 JanuaryEvening Shift
Exam
JEE Main
Year
2026
Date
23 January
Shift
Evening Shift
Subject
Mathematics
Chapter
Sets and Relations

JEE Main 2026 · 23 January · Evening Shift · Mathematics · Sets and Relations

Let A=\ 0,1,2, , 9\ . Let R be a relation on A defined by (x, y) ∈...

Let A={0,1,2,…,9}\mathrm{A}=\{0,1,2, \ldots, 9\}. Let R be a relation on A defined by (x,y)∈R(x, y) \in \mathrm{R} if and only if ∣x−y∣|x-y| is a multiple of 3. Given below are two statements:
Statement I: n(R)=36n(\mathrm{R})=36.
Statement II: RR is an equivalence relation.
In the light of the above statements, choose the correct answer from the options given below

Options

  1. AStatement I is incorrect but Statement II is correct
  2. BStatement I is correct but Statement II is incorrect
  3. CBoth Statement I and Statement II are incorrect
  4. DBoth Statement I and Statement II are correct

Correct answer

A. Statement I is incorrect but Statement II is correct

Step-by-step solution

The relation RR on A={0,1,2,…,9}A = \{0,1,2,\ldots,9\} is defined by (x,y)∈R(x,y) \in R iff ∣x−y∣|x-y| is a multiple of 3, i.e., x≡y(mod3)x \equiv y \pmod{3}.
Statement II:
RR is reflexive (∣x−x∣=0|x-x|=0, a multiple of 3), symmetric (∣x−y∣=∣y−x∣|x-y|=|y-x|), and transitive (if x≡yx \equiv y and y≡z(mod3)y \equiv z \pmod{3}, then x≡z(mod3)x \equiv z \pmod{3}). So RR is an equivalence relation. Statement II is correct.
Statement I:
The equivalence classes are {0,3,6,9}\{0,3,6,9\} (4 elements), {1,4,7}\{1,4,7\} (3 elements), {2,5,8}\{2,5,8\} (3 elements).
n(R)=42+32+32=16+9+9=34≠36n(R) = 4^2 + 3^2 + 3^2 = 16 + 9 + 9 = 34 \neq 36. Statement I is incorrect.
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