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JEE Main 20208 JanuaryMorning Shift
Exam
JEE Main
Year
2020
Date
8 January
Shift
Morning Shift
Subject
Mathematics
Chapter
Statistics

JEE Main 2020 · 8 January · Morning Shift · Mathematics · Statistics

The mean and the standard deviation (s.d.) of 10 observations are...

The mean and the standard deviation (s.d.)of10of 10 observations are 2020 and 22 respectively. Each of these 1010 observations is multiplied by pp and then reduced by q,q, where p≠0p \ne 0 and q≠0.q \ne 0 . If the new mean and new s.d. become half of their original values, then qq is equal to

Options

  1. A−5- 5
  2. B1010
  3. C−20- 20
  4. D−10- 10

Correct answer

C. −20- 20

Step-by-step solution

If each observation is multiplied with pp & then qq is subtracted, then
New mean x−1=px−−q{\overset{-}{x}}_{1} = p\overset{-}{x} - q
⇒10=p(20)−q.....(1)⇒ 10 = p\left(20\right) - q . . . . . \left(1\right)
and new standard deviation
σ2=∣p∣σ1⇒1=∣p∣(2)⇒∣p∣=12⇒p=±12{\sigma}_{2} = \left|p\right|{\sigma}_{1} ⇒ 1 = \left|p\right|\left(2\right) ⇒ \left|p\right| = \dfrac{1}{2} ⇒ p = \pm \dfrac{1}{2}
If p=12p = \dfrac{1}{2}
then q=0q = 0 (from equation (1))
If p=−12p = - \dfrac{1}{2}
q=−20q = - 20
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