JEE Main20198 Apr 2019Evening ShiftMathematicsStatisticsActual
A student scores the following marks in five tests: 45,54,41,57,43 . His score is not known for the sixth test. If the mean score is 48 in the six tests, then the standard deviation of the marks in six tests is:
Options
- A10 3
- B100 3
- C10 3
- D100 3
Correct answer
C. 10 3
Step-by-step solution
Given mean of 6 observations is 48 ⇒   41 + 45 + 54 + 57 + 43 + x 6 = 48 ⇒ x = 48 Now variance σ 2 = ∑ x - x 2 n = 7 2 + 3 2 + 6 2 + 9 2 + 5 2 + 0 2 6 = 100 3 Hence standard deviation = 10 3 .