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JEE Main 201815 April
Exam
JEE Main
Year
2018
Date
15 April
Subject
Mathematics
Chapter
Statistics

JEE Main 2018 · 15 April · Mathematics · Statistics

The mean of a set of 30 observation is 75 . If each observations is...

The mean of a set of 3030 observation is 7575. If each observations is multiplied by non-zero number λ\lambda and then each of them is decreased by 2525, their mean remains the same. Then, λ\lambda is equal to :

Options

  1. A43\dfrac{4}{3}
  2. B13\dfrac{1}{3}
  3. C103\dfrac{10}{3}
  4. D23\dfrac{2}{3}

Correct answer

A. 43\dfrac{4}{3}

Step-by-step solution

Let 3030 observations be x1,x2,.....…,x30{x}_{1}, {x}_{2}, . . . . . \ldots , {x}_{30}.

Given mean =75= 75

⇒x1+x2+…+x30=75×30⇒ {x}_{1} + {x}_{2} + \ldots + {x}_{30} = 75 \times 30

Now according to question,

λ(x1+x2+…+x30)−25×3030=75×3030\dfrac{\lambda ( {x}_{1} + {x}_{2} + \ldots + {x}_{30} ) - 25 \times 30}{30} = \dfrac{75 \times 30}{30}

⇒λ(75×30)=100×30⇒ \lambda\left(75 \times 30\right) = 100 \times 30

⇒λ=43⇒ \lambda = \dfrac{4}{3}

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